InstantForum.NET v4.1.4Y-BlocksForever Forumhttp://www.y-blocksforever.com/forums/jculver@y-blocksforever.comWed, 08 Feb 2012 22:37:09 GMT20http://www.y-blocksforever.com/forums/Topic39295-3-1.aspx<P style="MARGIN: 0in 0in 0pt" class=MsoNormal><SPAN style="FONT-SIZE: 12pt"><FONT face="Times New Roman"><FONT color=#000000>Once you find the theoretical diameter by measuring the circumference of the irregular sized hole, the rest of the calculation is treated like a circle.<SPAN style="mso-spacerun: yes"> </SPAN>You didn’t mention the gasket thickness, but with a 4.237” diameter hole and a 0.041” thick gasket, head gasket cc’s will be 9.47cc’s.<?xml:namespace prefix = o ns = "urn:schemas-microsoft-com:office:office" /><o:p></o:p></FONT></FONT></SPAN></P><P style="MARGIN: 0in 0in 0pt" class=MsoNormal><SPAN style="FONT-SIZE: 12pt"><FONT face="Times New Roman"><FONT color=#000000></FONT></FONT></SPAN> </P><P style="MARGIN: 0in 0in 0pt" class=MsoNormal><SPAN style="FONT-SIZE: 12pt"><FONT face="Times New Roman"><FONT color=#000000>Here’s the calculation.<o:p></o:p></FONT></FONT></SPAN></P><FONT color=#000000><SPAN style="FONT-FAMILY: 'Times New Roman'; FONT-SIZE: 10pt; mso-fareast-font-family: 'MS Mincho'; mso-ansi-language: EN-US; mso-fareast-language: EN-US; mso-bidi-language: AR-SA; mso-bidi-font-size: 12.0pt">(</SPAN><SPAN style="FONT-FAMILY: 'Times New Roman'; FONT-SIZE: 12pt; mso-fareast-font-family: 'MS Mincho'; mso-ansi-language: EN-US; mso-fareast-language: EN-US; mso-bidi-language: AR-SA">4.237) X (4.237) X (0.041") X (12.87) = 9.47cc</SPAN></FONT>Sun, 07 Feb 2010 08:28:10 GMTTedhttp://www.y-blocksforever.com/forums/Topic39295-3-1.aspxI've searched the forum and couldn't find an answer to my question:<br><br>Due to the irregular shape of the head gasket bore opening can someone tell me the correct diameter to enter into the compression ratio calculation formula? I measured the length of the opening with a piece of string and it is 13 5/16". If this was considered to be the circumference of a circle, the diameter would be 4.237". But is an irregular shape treated differently. I just barely scraped through geometry in H.S. and that was a long time ago!!! :unsure:Thanks.<br><br><br><br>Sun, 07 Feb 2010 08:01:35 GMTPhilo